Sunday, April 1, 2007

The Problem Book-2


2.) The wife of W.D. Fard's uncle, in the wilderness of North America, weighs other than herself, therefore, she has rheumatism, headaches, pain in all joints, and cannot walk up to the store. She is troubled frequently with high blood pressure and registers more than thirty-two. Her pulse is nearly eighty times per minute and she died at the age of forty-seven. How many times did her pulse beat in forty-seven years?

5 comments:

Kofi said...

Well assuming the same thing that I did in the previous problem I would say the answer is somewhere around
1,976,256,000

ABSA said...

Their is absolutely no way to determine that, unless you know the persons heart rate at the moment she was conceived, until her last heart beat. No persons heart rate beats at the exact same rate for every second of their physical existence.

Douglas Jordan said...

GIVEN THE FIRST PROBLEM, THE ANSWER FOR THE PULSE BEAT IN 47 YEARS WOULD BE AT THE AVERAGE HEART RATE OF 80 BPMS:
THEREFORE, 80 BPMs x 525,600 (TOTAL MINUTES FOR 1 YEAR) = 42,048,000
x 47 (YEARS OF AGE) =
APPROXIMATELY PLUS OR MINUS 1,976,256,000 OR 2 BILLION PULSE BEATS.

Yusuf said...

ANSWER:
Her pulse beat 1,977,609,600 times in forty-seven years.

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PROOF:
[Using the following rules:]
60 minutes = 1 hour
24 hours = 1 day
365.25 days = 1 year

80 bpm x 60 minutes = 4,800 beats per hour;
4,800 x 24 hours = 115,200 beats per day;
115,200 x 365.25 days = 42,076,800 beats per year;
42,076,800 x 47 years = 1,977,609,600 times.
(One billion, nine-hundred seventy-seven million, six hundred nine thousand, six hundred times.)

*Notes: Since we are calculating for several years, it is important to account for leap years; hence, 365.25 days.
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Maury said...

What does "registers at 32" mean?